Choosing a term length around your child's college date

The length of a term policy should come from a date, not from a feeling. Most parents pick 20 years because it is the middle choice, then find out later that it ended before the last tuition bill or the last mortgage payment. This worksheet gives you a method to find the date your coverage must reach, with blanks to fill in and two worked examples so you can check your arithmetic.

It answers one question: how many years of coverage do I need? It does not decide how much coverage to buy, which is a separate calculation covered in The DIME method for sizing life insurance and in the planning post adding a college fund to your coverage amount without overbuying. Every dollar figure below is an invented illustration, not a price.

Step 1: write down the obligations that need an end date

The reason to insure a parent's life is to keep certain promises if that parent is not there to keep them. Each promise has a date when it is fulfilled and no longer depends on your paycheck. List yours. For a parent with a young child, the usual four are:

1. The last tuition or college payment. This is the date your youngest child finishes the schooling you intend to fund, not the date they start.
2. The mortgage or other large debt. The date the loan is paid off, or the date you expect to sell or refinance the house.
3. Income replacement for a spouse. The date your household would no longer rely on your earnings, usually your planned retirement date or the date your savings could replace your income.
4. Any other fixed commitment. Support for a parent, payments under a divorce decree, a business loan.

You need an end date for each one. Fill in this table with your own numbers:

How to fill in the tuition row

Take the age at which your youngest child will make the last payment you plan to cover and subtract their age today. For a four-year degree that starts at 18, the last payment is often around 21 or 22. For graduate school, trade school or a plan to cover only the first two years, use the age that matches your intention.

If the child is 3 and you plan to cover through age 22, the row reads 22 - 3 = 19 years. If the child is 9 and your plan is the same, the row reads 22 - 9 = 13 years.

Your goal here is the point at which a death would no longer leave the child without the college money. If you have saved enough by then that the funds are already in an account, the obligation has effectively ended earlier, and that is covered in Step 3.

Step 2: add a margin

A term policy that expires on the day of the final payment leaves no room for a delay. The child might take a fifth year, switch programs or go to graduate school. The mortgage might be extended after a refinance. Add a margin of one or two years to each row.

Also remember that the term starts on the day the policy is issued, not the day you decide to buy. If it will take three months to apply and be underwritten, the clock starts then. For a 20-year policy, that cost is trivial, but it matters when the margin is already thin.

Fill in the margin column:

Step 3: find the binding date

The number you need is the largest figure in the last column, because coverage must run until the last obligation ends. That is the binding date. Circle it.

There is one adjustment before you commit to it. Obligations shrink as you pay them down, and savings accumulate. The late years of a long term often protect a much smaller need than the early years. For example, in year 19 of a plan, the mortgage balance may be a small fraction of its original size and the college fund may be fully paid. If the binding date comes from an obligation that is nearly paid off, the answer may be a smaller second policy that runs longer, which is a simple two-policy version of the approach described in laddering term life policies to match your needs and in the worksheet post build a three-policy term ladder with your own numbers.

Step 4: match the date to a term length

Insurers commonly sell terms of 10, 15, 20, 25 and 30 years, although the exact list varies by company and some offer terms to a specific age. Round your binding date up to the next available length. Never round down.

If your date falls just over a boundary, say 21 years, you have a real choice between paying for the longer term or covering the gap another way. We test both ideas in the examples.

Worked example 1: a parent of a three-year-old

Say Ana, 36, has a daughter, Maya, who is 3. Ana owes 24 more years on a mortgage, plans to retire at 65, and wants Maya's college covered through age 22.

The largest figure is 29 years, driven by Ana's retirement date. But the household has savings goals, and Ana and her husband expect their retirement accounts to be on track by about year 20 even if they have to stop contributing. They decide that the income replacement obligation really ends when the mortgage ends, so their binding date is the mortgage figure: 25 years.

The shortest term that covers 25 years is 25 years. Now test the options.

Testing 15, 20 and 25-year terms

For this example, say each policy is $500,000 and the premiums are an illustrative $27 a month for 15 years, $32 for 20 and $42 for 25. These are round numbers chosen to show the pattern that longer terms cost more per month, not real quotes. Total premiums over each full term:

• 15-year: $27 × 12 months × 15 years = $4,860
• 20-year: $32 × 12 × 20 = $7,680
• 25-year: $42 × 12 × 25 = $12,600

The 15-year policy fails both tests. The 20-year policy is the common default, and it covers college but not the mortgage, so Ana would be insured for the first and uninsured for the second at the moment her coverage ends. The 25-year policy fits the plan.

A two-policy alternative

Ana notices that after year 15 her need falls. By then Maya is 18, the college fund has received 15 years of contributions, and the mortgage balance is lower. Say she estimates she needs $500,000 for the first 15 years and $250,000 afterward. She could buy two policies:

• $250,000 for 25 years at an illustrative $24 a month
• $250,000 for 15 years at an illustrative $15 a month

Total premiums: $24 × 12 × 25 = $7,200, plus $15 × 12 × 15 = $2,700, which is $9,900. That compares with $12,600 for a single $500,000 25-year policy, a saving of $2,700 in this illustration.

The cost is paperwork and a step-down. There are two policies to manage, two conversion deadlines, and the death benefit falls to $250,000 in year 16. Maya turns 18 in year 15, so her college years run from year 15 through year 19, and the step-down lands in the middle of them. If the college fund is mostly built by then, a lower amount may be enough. If not, Ana can make the short layer a 20-year policy instead, at an illustrative $18 a month:

• $24 × 12 × 25 = $7,200 for the 25-year layer
• $18 × 12 × 20 = $4,320 for the 20-year layer
• Total: $7,200 + $4,320 = $11,520, which is $1,080 less than the single policy

This is how the worksheet is meant to work: it turns a vague preference into a comparison you can check. The tool at How long a term do I need? lets you test lengths against your own dates.

Worked example 2: a parent of a nine-year-old

Say Jordan, 41, has a son, Eli, who is 9. Jordan plans to cover tuition through age 22, owes 12 more years on the mortgage, and expects to retire at 67.

If Jordan treats retirement as the binding date, the answer is 26 years, which rounds up to a 30-year term. But Jordan's retirement accounts are well funded, and the household would not need his income replaced beyond the end of college. The tuition row sets the date at 15 years. The shortest term that covers it is 15 years.

Test the two nearest lengths against Jordan's rows. The 15-year policy covers the tuition row (15 years to cover) and the mortgage row (13), with no gap and no spare years beyond the margins already built in. A 20-year policy would add five years of coverage that protect only Jordan's income replacement, which he has decided is already handled by savings. Using the same illustrative $500,000 premiums as the first example ($27 a month for 15 years, $32 for 20), the extra outlay over the full terms is ($32 × 12 × 20) - ($27 × 12 × 15) = $7,680 - $4,860 = $2,820. Jordan can then ask a plain question: is $2,820 a fair price for five years of cover he believes he does not need?

Here the nine-year-old's age made a large difference. The same household with a 3-year-old would have needed 20 or 25 years. The method gives different answers because the inputs are different, which is the reason to run it with your own.

Two sanity checks before you apply

Check the start date. Count from the day the policy will be issued, which is the day coverage begins, not the day you read this. If you are still in the process of deciding, a year of delay shortens every year of coverage you can buy by a year in practice, because your child is a year older and your mortgage a year shorter. A worksheet done a year late gives a shorter binding date, which can lower the term you need. It does not mean waiting is free. Premiums are set by your age and health on the day you apply, so a year of waiting can raise the price per month, and a health problem in the meantime can change the answer completely.

Check what each year of extra length actually buys. Compare the 20-year and 25-year rows in the first example: the five extra years cost $12,600 - $7,680 = $4,920 in total premiums in this illustration. That is the price of covering the final five years of the mortgage. Whether it is worth it depends on how large the mortgage balance is in those years and whether the family could pay it from savings, a spouse's income or the sale of the house. If the balance by then is small, a smaller second policy or a conscious decision to self-insure the tail may be better value. If the balance is large and no one could cover it, the extra length is cheap protection. Either way, you are choosing with the numbers in front of you.

Where this worksheet can mislead you

A method this simple has limits. Four to watch:

• The income replacement row is a judgment call. Choosing the retirement date versus the date savings catch up changes the answer by many years. If in doubt, ask a fee-only planner to test it.
• New obligations appear. A second child restarts the tuition clock. A remarriage or a new loan adds a row. Revisit the worksheet when your family changes.
• The conversion right matters. If your binding date is later than your term, check the conversion privilege deadline, since the right to convert into permanent coverage may expire before the term does. how long a term should you buy: 10, 20 or 30 years covers how to weigh term length against that.
• Funding college with life insurance is a different question. This worksheet insures the plan to pay for college. It does not use the policy as the savings account. The trade-offs of the latter are in life insurance as a college savings tool: the trade-offs.

If the mortgage is the item that sets your date, the logic in using term life insurance to cover a mortgage explains how to size the coverage to the balance.

A blank copy to keep

Copy these lines onto paper and fill them in:

1. Youngest child's age today: ____. Age at last payment I plan to cover: ____. Years: ____ + 2 margin = ____.
2. Years remaining on mortgage: ____ + 1 margin = ____.
3. Years until my income no longer needs replacing: ____.
4. Other obligation, years: ____.
5. Binding date (the largest of lines 1 to 4): ____.
6. Shortest available term that covers it: ____.
7. Years of coverage my current policy has left, if I have one: ____.

Key takeaways

• Choose the term length from the latest date you must protect, and add a one- or two-year margin for delays.
• The binding date is the largest of your end dates. Round up to an available term, never down.
• The age of your youngest child can change the answer by a decade, so redo the math whenever your family changes.
• A longer term costs more per month and in total, but a policy that ends before the mortgage leaves the largest bill unprotected.
• If the binding date comes from an obligation that is shrinking, test a two-policy approach before buying one long, large policy.